(x^2+2x+1)-(x^2+4x+3)=4

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Solution for (x^2+2x+1)-(x^2+4x+3)=4 equation:


Simplifying
(x2 + 2x + 1) + -1(x2 + 4x + 3) = 4

Reorder the terms:
(1 + 2x + x2) + -1(x2 + 4x + 3) = 4

Remove parenthesis around (1 + 2x + x2)
1 + 2x + x2 + -1(x2 + 4x + 3) = 4

Reorder the terms:
1 + 2x + x2 + -1(3 + 4x + x2) = 4
1 + 2x + x2 + (3 * -1 + 4x * -1 + x2 * -1) = 4
1 + 2x + x2 + (-3 + -4x + -1x2) = 4

Reorder the terms:
1 + -3 + 2x + -4x + x2 + -1x2 = 4

Combine like terms: 1 + -3 = -2
-2 + 2x + -4x + x2 + -1x2 = 4

Combine like terms: 2x + -4x = -2x
-2 + -2x + x2 + -1x2 = 4

Combine like terms: x2 + -1x2 = 0
-2 + -2x + 0 = 4
-2 + -2x = 4

Solving
-2 + -2x = 4

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '2' to each side of the equation.
-2 + 2 + -2x = 4 + 2

Combine like terms: -2 + 2 = 0
0 + -2x = 4 + 2
-2x = 4 + 2

Combine like terms: 4 + 2 = 6
-2x = 6

Divide each side by '-2'.
x = -3

Simplifying
x = -3

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